![]() Which method you choose affects the outcome of the. The pathfinder tool will still mess with the shape stacking order, but this way it will be irrelevant because the two shapes being shuffled around are both ultimately in the part of the stacking order that the pathfinder result will occupy. You can apply Illustrators Pathfinder effects from the Pathfinder panel or the programs Effects menu. To make compound shapes, use the buttons in those rows while pressing the Alt or Option key. ![]() Pathfinder panel Use the top row of buttons in the panel to make paths or compound paths. Paste shape A directly in front of shape C in the layer order (Copy Shape A, select Shape C, select past in front /CMD+F) - then perform the transform. Navigate the Pathfinder panel You use the Pathfinder panel (Window > Pathfinder) to combine objects into new shapes. *A is no longer in present as the Minus Front tool causes the shape you are cutting out with to disappear. (furthest forward) Shape C - (furthest forward) - Shape that you have created by removing shape A* But thats not the case this tool has no relation to finding paths So why did Adobe name the tool as pathfinder Well, it is still a question left. Then the pathfinder tool will cause 'Shape C - (the shape being cut into)' to jump forward to wherever in the layer order 'Shape A - (the shape doing the cutting)' was. If it isnt already open, you can open it by going to Window > Pathfinder or by using the. If youre experiencing the same issue that I am, then youll f. Get started by opening your background image on your canvas. Click the Pathfinder panel, and select Unite. ![]() (furthest back) Shape C - Shape that you are wanting to alter/remove Shape A from Apply a 30 pt stroke to it, and align that stroke to the outside of the shape. (furthest forward) Shape A - Shape that you are wanting to remove from Shape C Illustrator keeps giving me a 'Pathfinder effects should usually be applied to groups, layers or type objects. The problem is that if the object/layer stacking order is this:
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